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(x+5)(x-1)=(x+1)^2
We move all terms to the left:
(x+5)(x-1)-((x+1)^2)=0
We multiply parentheses ..
(+x^2-1x+5x-5)-((x+1)^2)=0
We calculate terms in parentheses: -((x+1)^2), so:We get rid of parentheses
(x+1)^2
x^2-1x+5x-((x+1)^2)-5=0
We calculate terms in parentheses: -((x+1)^2), so:We add all the numbers together, and all the variables
(x+1)^2
x^2+4x-((x+1)^2)-5=0
We calculate terms in parentheses: -((x+1)^2), so:
(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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